okay, okay..........
let me redo my math..
IF at the current rate we are posting: fred's = 627 posts outta 1153 and kay's = 526 posts outta 1153
OR fred's =posts 54.437% of times compared to kay's = 45.563%. (rounding off)
fred's = 54% and kay's = 46%
so out of 4000+ posts
fred's = 2160 total posts whereas kay' would equal 1840 posts
but we now need to consider "content":
fred's "content" (on a scale of 1-10) is a 7.3 whereas kay's would be 8.7.
Now factoring into the equation the variable "content"
fred's total posts factor times 7.3 times Van Murchin indexes of 0.000347812.
fred's total post would go down to 1921 and kay's would raise to 2079.
finally picture quality rating for fred's = 0.93 whereas kay's =0.99.7 times the inverse brings the total posts for kay to 2001 whereas fred is slightly behind at 1999.
*checking my math*.................. yeap, that just about does it!
(who said a little knownledge is dangerous? -- and fred's has as little as anyone?)
and..................Can you get the pretzels?
and.................... Oh yea? I got more beer! forget the "frig" I got US a keg instead.............. please to draw, me and yourself, a beer now?